How do you simplify #(1)^ -2/(8) ^ -2#?

Question

1458 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-07T21:42:04

#64#

The numerator just evaluates to #1#, thus we're left with

#1/8^-2#

We can make the negative exponent positive by bringing it to the numerator. We get

#1*8^2#

which evaluates to

#64#

Hope this helps!

Answer 2 · 2018-06-07T21:45:12

64

Quotient rule for exponents:

#1/x^n = x^-n/1#

#(1)^-2/(8)^-2=8^-(-2)/1^-(-2)=8^2/1^2=64/1=64#