How do you simplify $\frac{{(1)}^{- 2}}{{(8)}^{- 2}}$ $(1)^ -2/(8) ^ -2$ ?

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How do you simplify $\frac{{(1)}^{- 2}}{{(8)}^{- 2}}$ $(1)^ -2/(8) ^ -2$ ?

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Answer 1 · 2018-06-07T21:42:04

$64$ $64$

Explanation:

The numerator just evaluates to $1$ $1$ , thus we're left with

$\frac{1}{8^{- 2}}$ $1/8^-2$

We can make the negative exponent positive by bringing it to the numerator. We get

$1 \cdot 8^{2}$ $1*8^2$

which evaluates to

$64$ $64$

Hope this helps!

Answer 2 · 2018-06-07T21:45:12

64

Explanation:

Quotient rule for exponents:

$\frac{1}{x^{n}} = \frac{x^{- n}}{1}$ $1/x^n = x^-n/1$

$\frac{{(1)}^{- 2}}{{(8)}^{- 2}} = \frac{8^{- (- 2)}}{1^{- (- 2)}} = \frac{8^{2}}{1^{2}} = \frac{64}{1} = 64$ $(1)^-2/(8)^-2=8^-(-2)/1^-(-2)=8^2/1^2=64/1=64$

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How do you simplify $\frac{{(1)}^{- 2}}{{(8)}^{- 2}}$ $(1)^ -2/(8) ^ -2$ ?

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