How do you simplify #(1+2v) times 5#?
1 Answer
Aug 13, 2016
Explanation:
Usually written 5(1 + 2v)
each of the 2 terms inside the bracket must be multiplied by the 5.
#color(red)(5)(1+2v)=(color(red)(5)xx1)+(color(red)(5)xx2v)#
#rArr5(1+2v)=5+10v#