How do you simplify ${(1 + 3 \cdot 3)}^{2} + 8$ $(1+3*3)^2 + 8$ ?

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Answer 1 · 2015-04-07T04:31:40

Carry out the operations inside the parentheses first. Square the result, then add the 8.

${(1 + 3 \cdot 3)}^{2} + 8 = {(1 + 9)}^{2} + 8 = {(10)}^{2} + 8 = 100 + 8 = 108$ $(1+3*3)^2+8=(1+9)^2+8=(10)^2+8=100+8=108$

How do you simplify (1+3⋅3)2+8(1+3*3)^2 + 8?