How do you simplify ${(\frac{1}{32})}^{- \frac{2}{5}}$ $(1/32)^(-2/5)$ ?

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How do you simplify ${(\frac{1}{32})}^{- \frac{2}{5}}$ $(1/32)^(-2/5)$ ?

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Answer 1 · 2015-10-07T17:56:46

I found $4$ $4$

Explanation:

We can write this expression into a root form (fractional exponent) and get rid of the $-$ $-$ sign inverting the original fraction as:
${(\frac{1}{32})}^{- \frac{2}{5}} = {(32)}^{\frac{2}{5}} = \sqrt[5]{32^{2}} = \sqrt[5]{32 \cdot 32} = \sqrt[5]{32} \sqrt[5]{32} = 2 \cdot 2 = 4$ $(1/32)^(-2/5)=(32)^(2/5)=root5(32^2)=root5(32*32)=root5(32)root5(32)=2*2=4$

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How do you simplify ${(\frac{1}{32})}^{- \frac{2}{5}}$ $(1/32)^(-2/5)$ ?

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