How do you simplify $\frac{1}{3 p^{- 4}}$ $1/(3p^-4)$ ?

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Answer 1 · 2016-03-09T21:09:15

$\frac{p^{4}}{3}$ $p^4/3$

A negative exponent denotes:

$a^{- b} = \frac{1}{a^{b}}$ $a^-b=1/a^b$

Yielding the expression:

$= \frac{1}{3 (\frac{1}{p^{4}})}$ $=1/(3(1/p^4)$

To simplify this, multiply the fraction by $\frac{p^{4}}{p^{4}}$ $p^4/p^4$ :

$= \frac{1}{3 (\frac{1}{p^{4}})} (\frac{p^{4}}{p^{4}})$ $=1/(3(1/p^4))(p^4/p^4)$

The denominator equals

$= 3 (\frac{1}{p^{4}}) (p^{4}) = 3$ $=3(1/p^4)(p^4)=3$

since $\frac{1}{p^{4}} (p^{4}) = 1$ $1/p^4(p^4)=1$ .

Since the numerator is just $p^{4}$ $p^4$ , the simplified expression equals

$= \frac{p^{4}}{3}$ $=p^4/3$

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