How do you simplify $(1/h^-2)^-1*h^3$ ?

Question

3546 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-09T22:18:18

$h$

Given that

$(1/h^{-2})^{-1}\cdot h^3$

$=(h^{-2})^{1}\cdot h^3$

$=h^{-2}\cdot h^3$

$=h^{-2+3}$

$=h$

Answer 2 · 2018-07-09T22:23:38

$h$

Given: $(1/h^-2)^-1 * h^3$

Use the exponent rules: $1/x^-n = x^n; " " x^-m = 1/x^m$

$(x^m)^n = x^(m*n); " "x^nx^m = x^(n+m)$

$(1/h^-2)^-1 * h^3 = (h^2)^-1 * h^3 = h^-2 * h^3$

$h^(-2 + 3) = h^1 = h$

How do you simplify (1/h^-2)^-1*h^3(1/h^-2)^-1*h^3?