How do you simplify $- 10 \div 5 \cdot 2 + 8 \cdot (6 - 4) - 3 \cdot 4$ $-10div52+8(6-4)-3*4$ ?

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Answer 1 · 2015-04-14T07:51:28

We use the PEMDAS rule to simplify the above expression
(Parentheses>Exponents>Multiply and Divide>Add or Subtract)

$- 10 \div 5 \cdot 2 + 8 \cdot (6 - 4) - 3 \cdot 4$ $-10div5*2+8*(6-4)-3*4$

We solve the Parentheses first

$= - 10 \div 5 \cdot 2 + 8 \cdot 2 - 3 \cdot 4$ $= -10div5*2+8*2-3*4$

We then Multiply/Divide whichever comes first

$= - 2 \cdot 2 + 8 \cdot 2 - 3 \cdot 4$ $= -2*2+8*2-3*4$

$= - 4 + 8 \cdot 2 - 3 \cdot 4$ $= -4+8*2-3*4$

$= - 4 + 16 - 3 \cdot 4$ $= -4+16-3*4$

$= - 4 + 16 - 12$ $= -4+16-12$

We then Add/Subtract whichever comes first

$= 12 - 12$ $= 12-12$

$= 0$ $= 0$

$- 10 \div 5 \cdot 2 + 8 \cdot (6 - 4) - 3 \cdot 4 = 0$ $color(green)(-10div5*2+8*(6-4)-3*4 = 0$

How do you simplify −10÷5⋅2+8⋅(6−4)−3⋅4-10div5*2+8*(6-4)-3*4?