How do you simplify #-10div52+8(6-4)-3*4#?

Question

1566 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-14T07:51:28

We use the PEMDAS rule to simplify the above expression
(Parentheses>Exponents>Multiply and Divide>Add or Subtract)

#-10div5*2+8*(6-4)-3*4#

We solve the Parentheses first

#= -10div5*2+8*2-3*4#

We then Multiply/Divide whichever comes first

# = -2*2+8*2-3*4#

# = -4+8*2-3*4#

# = -4+16-3*4#

# = -4+16-12#

We then Add/Subtract whichever comes first

# = 12-12#

# = 0#

#color(green)(-10div5*2+8*(6-4)-3*4 = 0#

How do you simplify #-10div5*2+8*(6-4)-3*4#?