How do you simplify #(11y) * 5#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Alan P. Sep 11, 2015 #(11y)*5 = 55y# Explanation: #11y# means #11xxy# #(11y)*5# means #11xxyxx5# By the commutative property #=11xx5xxy# and since #11xx5 = 55# #=55xxy# or #55y# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 2358 views around the world You can reuse this answer Creative Commons License