How do you simplify #12 [10 - (5^2 - 6) 3 div6]# using PEMDAS?

Question

1441 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-15T02:00:43

See the entire simplification process below:

First, we need to handle the inner Parenthesis and Exponents (PE), taking the Exponents first:

#12[10 - (5^2 - 6)3 -: 6] = 12[10 - (25 - 6)3 -: 6] = #

#12[10 - (19)3 -: 6] = 12[10 - 19 xx 3 -: 6]#

Next, within the brackets (another form of Parethesis) we need to handle the Multiplication and Division (MD) next, moving left to right:

#12[10 - (19 xx 3) -: 6] = 12[10 - (57 -: 6)] = 12[10 - 9.5]#

Then, within the brackets again we can deal with the Addition and Subtraction (AS):

#12[10 - 9.5] = 12[0.5] = 12 xx 0.5 = 6#