How do you simplify $12 [10 - (5^{2} - 6) 3 \div 6]$ $12 [10 - (5^2 - 6) 3 div6]$ using PEMDAS?

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Answer 1 · 2017-02-15T02:00:43

See the entire simplification process below:

First, we need to handle the inner Parenthesis and Exponents (PE), taking the Exponents first:

$12 [10 - (5^{2} - 6) 3 \div 6] = 12 [10 - (25 - 6) 3 \div 6] =$ $12[10 - (5^2 - 6)3 -: 6] = 12[10 - (25 - 6)3 -: 6] =$

$12 [10 - (19) 3 \div 6] = 12 [10 - 19 \times 3 \div 6]$ $12[10 - (19)3 -: 6] = 12[10 - 19 xx 3 -: 6]$

Next, within the brackets (another form of Parethesis) we need to handle the Multiplication and Division (MD) next, moving left to right:

$12 [10 - (19 \times 3) \div 6] = 12 [10 - (57 \div 6)] = 12 [10 - 9.5]$ $12[10 - (19 xx 3) -: 6] = 12[10 - (57 -: 6)] = 12[10 - 9.5]$

Then, within the brackets again we can deal with the Addition and Subtraction (AS):

$12 [10 - 9.5] = 12 [0.5] = 12 \times 0.5 = 6$ $12[10 - 9.5] = 12[0.5] = 12 xx 0.5 = 6$

How do you simplify 12[10−(52−6)3÷6]12 [10 - (5^2 - 6) 3 div6] using PEMDAS?