How do you simplify $\frac{14 x^{5} y}{2 x y^{- 2}}$ $(14x^5y)/(2xy^ -2)$ ?

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Answer 1 · 2015-09-27T09:28:26

$= 7 x^{4} y^{3}$ $=color(blue)(7x^4y^3$

$\frac{14 x^{5} y}{2 x y^{- 2}}$ $(14x^5y)/(2xy^-2$

By property
$\frac{1}{a} = a^{- 1}$ $color(blue)(1/a =a^-1$ and,

$\frac{1}{a^{- 1}} = a$ $color(blue)(1/a^-1 =a$

$(14x^5y)/(2(color(blue)(xy^-2))) = (cancel14/cancel2) * (x^5y* color(blue)(x^-1 y^2))$

$=7 x^5y* color(blue)(x^-1 y^2)$

By property
$color(blue)(a^m*a^n = a^(m+n)$

$=7 x^color(blue)((5-1)) y^color(blue)((1+2))$

$=color(blue)(7x^4y^3$

How do you simplify (14x^5y)/(2xy^ -2)14x5y2xy−2 (14x^5y)/(2xy^ -2)?