How do you simplify #(15h^6k^3)/(5hk^2)# using only positive exponents? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer sankarankalyanam Mar 9, 2018 #=> color(green)(3h^5k)# Explanation: #(15h^6k^3) / (5hk^2)# #=> = (color(purple)(5) * 3* color(purple)(h) * h^5 * k* color(purple)(k^2)) / color(purple)(5 * h * k^2)# Taking #(3*h^5 * k)# outside the bracket in the numerator, #=>( (3h^5k) * cancel(color(red)((5hk^2)))) / cancel(color(red)((5hk^2) # #=> color(green)(3h^5k)# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1379 views around the world You can reuse this answer Creative Commons License