Question

How do you simplify `16^(2/3)`?

Answer 1

`16^(2/3)=4root(3)(4)`

Explanation:

A fractional exponent with `n` in the denominator is equivalent to taking the `n^"th"` root of the base. Then, together with the property that `x^(ab) = (x^a)^b` we have

`16^(2/3) = (16^2)^(1/3)`

`=root(3)(256)`

`=root(3)(4^3*4)`

`=4root(3)(4)`