How do you simplify $16 \div 4 \times 2 - 7$ $16 ÷ 4 times 2 - 7$ using PEMDAS?

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Answer 1 · 2016-07-29T14:02:07

Corrected answer

$16 \div 4 \times 2 - 7 = 1$ $" "16-:4xx2-7" " =" " 1$

Using strict application of process

P $\to$ $->$ Parenthesise (brackets)
E $\to$ $->$ Exponents (powers)
M $\to$ $->$ Multiply
D $\to$ $->$ Divide
A $\to$ $->$ Add
S $\to$ $->$ Subtract

I am advised that it is better to write this as

P-E-MD-AS as multiply and divide have the same priority. As do add and subtract.

Given: $16 \div 4 \times 2 - 7$ $" "16-:4xx2-7$

So reading left to right

$\Rightarrow [(16 \div 4) \times 2] - 7$ $=>[(16-:4)xx2]-7$

$\Rightarrow [4 \times 2] - 7$ $=>[4xx2]-7$

$\Rightarrow 8 - 7 = 1$ $=>8-7 = 1$

How do you simplify 16÷4×2−716 ÷ 4 times 2 - 7 using PEMDAS?