How do you simplify #(-16a^5b^3)/(-24a^5b^7)#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Don't Memorise Jun 18, 2015 # = color(blue)(2/3b^(-4)# Explanation: #(-16a^5b^3)/(-24a^5b^7)# # = ((-cancel16)/-cancel24) . (cancel(a^5/a^5)) . (b^3/b^7)# # = (2/3) . color(blue)(b^3/b^7# Note: # color(blue)(a^m/a^n= a^(m-n)# Applying the above to the exponents of #b# # = (2/3) color(blue)(b^(3-7)# # = 2/3 color(blue)(b^(-4)# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1395 views around the world You can reuse this answer Creative Commons License