How do you simplify $2^1000 - 2^999$ ?

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Answer 1 · 2018-05-29T14:57:43

$2^999$

We need to remember that:
$n^a xx n^b = n^(a+b)$

$n^a / n^b = n^(a-b)$

So here's what we gonna do

$2^1000 - 2^999$

$= (2) (2^999) - (1) (2^999)$

$= (2-1) (2^999)$

$= (2^999)$

Answer 2 · 2018-05-29T15:03:26

$x=2^999$

We take,

$x=2^(1000)-2^999$

$x=2^(999+1)-2^999$

$x=2^999*2^1-2^999...to[becausea^(m+n)=a^m*a^n]$

$x=2^999(2^1-1)$

$x=2^999(1)$

$x=2^999$

How do you simplify 2^1000 - 2^9992^1000 - 2^999?