How do you simplify $(2/3)^4/((2/3)^-5(2/3)^0)$ ?

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Answer 1 · 2016-12-04T17:40:25

$(2/3)^9$

When dividing monomials, you subtract the exponents. I'll show this step below:

$(2/3)^4/(2/3)^-5$ would equal $(2/3)$ to the ninth power, since $4-(-5) = 9$ , thus $(2/3)^4/((2/3)^-5)= (2/3)^9$ .

As for $(2/3)^0$ , that equals 1, since $x^0$ is 1, and anything times 1 is itself. Hope this helped.

How do you simplify (2/3)^4/((2/3)^-5(2/3)^0)(2/3)^4/((2/3)^-5(2/3)^0)?