How do you simplify $(\frac{2^{3}}{- 40 - 9.5}) - 3.5$ $(2^3/( -40- 9.5))- 3.5$ using PEMDAS?

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Answer 1 · 2017-03-21T20:07:22

See the entire solution process below:

First, simplify the Exponent term in the numerator of the fraction within the parenthesis:

$(\frac{2^{3}}{- 40 - 9.5}) - 3.5 = (\frac{8}{- 40 - 9.5}) - 3.5$ $(color(red)(2^3)/(-40 - 9.5)) - 3.5 = (8/(-40 - 9.5)) - 3.5$

Next, execute the subtraction in the denominator of the fraction within the Parenthesis:

$(\frac{8}{- 40 - 9.5}) - 3.5 \to (\frac{8}{- 49.5}) - 3.5$ $(8/(color(red)(-40 - 9.5))) - 3.5 -> (8 / -49.5) - 3.5$

Then, execute the division within the parenthesis:

$(\frac{8}{- 49.5}) - 3.5 \to - 0 . ¯ ¯¯ ¯ 16 - 3.5$ $(color(red)(8/-49.5)) - 3.5 -> -0.bar16 - 3.5$

Now, execute the remaining subtraction operation:

$- 0 . ¯ ¯¯ ¯ 16 - 3.5 = - 3.66 ¯ ¯¯ ¯ 16$ $color(red)(-0.bar16 - 3.5) = -3.66bar16$

How do you simplify (23−40−9.5)−3.5 (2^3/( -40- 9.5))- 3.5 using PEMDAS?