How do you simplify $2 - 3 [x - 2 - 5 (x - 1)]$ $2-3[x-2-5(x-1)]$ ?

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How do you simplify $2 - 3 [x - 2 - 5 (x - 1)]$ $2-3[x-2-5(x-1)]$ ?

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Answer 1 · 2015-07-01T19:08:00

I found: $12 x - 7$ $12x-7$

Explanation:

First multiply $- 5$ $-5$ :
$2 - 3 [x - 2 - 5 x + 5] =$ $2-3[x-2-5x+5]=$
add similar terms inside the square brackets:
$= 2 - 3 [3 - 4 x] =$ $=2-3[3-4x]=$
multiply $- 3$ $-3$ :
$= 2 - 9 + 12 x =$ $=2-9+12x=$
$= 12 x - 7$ $=12x-7$

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How do you simplify $2 - 3 [x - 2 - 5 (x - 1)]$ $2-3[x-2-5(x-1)]$ ?

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How do you simplify 2-3[x-2-5(x-1)]2−3[x−2−5(x−1)]2-3[x-2-5(x-1)]?

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How do you simplify $2 - 3 [x - 2 - 5 (x - 1)]$ $2-3[x-2-5(x-1)]$ ?