How do you simplify $\frac{2}{5} \cdot \frac{2}{3} + \frac{1}{5} \div \frac{2}{3}$ $2/5 * 2/3 +1/5 div 2/3$ ?

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Answer 1 · 2015-04-17T23:17:33

$\frac{2}{5} \cdot \frac{2}{3} + \frac{1}{5} \div \frac{2}{3}$ $2/5*2/3 + 1/5-:2/3$

$= \frac{4}{15} + \frac{1}{5} \cdot \frac{3}{2}$ $=4/15+1/5*3/2$

$= \frac{4}{15} + \frac{3}{10}$ $=4/15+3/10$

Now ask yourself the question, what do 15 and 10 both fit into?

*The answer is 30. So let's transform the denominators of these fractions into 30.

$= \frac{4}{15} \cdot 1 + \frac{3}{10} \cdot 1$ $=4/15*1+3/10*1$

$= \frac{4}{15} \cdot \frac{2}{2} + \frac{3}{10} \cdot \frac{3}{3}$ $=4/15*2/2+3/10*3/3$

$= \frac{8}{30} + \frac{9}{30}$ $=8/30+9/30$

$= \frac{17}{30}$ $=17/30$

How do you simplify 25⋅23+15÷232/5 * 2/3 +1/5 div 2/3?