How do you simplify $2 - 5 {(9 - 4 \cdot \sqrt{25})}^{2}$ $2-5(9-4*sqrt(25))^2$ using order of operations?

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Answer 1 · 2016-07-24T14:12:41

$2 - 5 {(9 - 4 \cdot \sqrt{25})}^{2} = - 603$ $2-5(9-4*sqrt25)^2=-603$

Let us simplify

$2 - 5 {(9 - 4 \cdot \sqrt{25})}^{2}$ $2-5(9-4*sqrt25)^2" "$ the given expression

$2 - 5 {(9 - 4 (5))}^{2}$ $2-5(9-4(5))^2" "$ we begin inside the grouping symbol exponentiation first

$2 - 5 {(9 - 20)}^{2}$ $2-5(9-20)^2" "$ we take the product of 4 and 5

$2 - 5 {(- 11)}^{2}$ $2-5(-11)^2" "$ we now have the difference between 9 and 20

$2 - 5 (121)$ $2-5(121)" "$ the square of $- 11$ $-11$ is 121

$2 - 605$ $2-605" "$ the product of 121 and 5 is 605

$- 603$ $-603" "$ final answer is the difference between 2 and 605 where 2 is the minuend and 605 the subtrahend.

How do you simplify 2−5(9−4⋅√25)22-5(9-4*sqrt(25))^2 using order of operations?