How do you simplify #(-2-6i)-(4-6i)#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Shwetank Mauria Aug 20, 2016 #(-2-6i)-(4-6i)=-6# Explanation: #(-2-6i)-(4-6i)# = #-2-6i-4+6i# - as we have a minus sign outside we have changed all the signs inside as it is equivalent to multiplying by #-1#. Hence above is equivalent to #-2-cancel(6i)-4+cancel(6i)# = #-2-4# = #-6# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 2144 views around the world You can reuse this answer Creative Commons License