How do you simplify ${(2 e^{- 2})}^{- 4}$ $(2e^-2)^-4$ ?

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Answer 1 · 2016-08-25T14:48:05

${(2 e^{- 2})}^{- 4} = \frac{e^{8}}{16}$ $(2e^(-2))^(-4)=e^8/16$

As $a^{- n} = \frac{1}{a^{n}}$ $a^(-n)=1/a^n$

${(2 e^{- 2})}^{- 4}$ $(2e^(-2))^(-4)$

= $\frac{1}{{(2 e^{- 2})}^{4}}$ $1/(2e^(-2))^4$

= $\frac{1}{2^{4} \times e^{- 8}}$ $1/(2^4×e^(-8))$

= $\frac{1}{16 e^{- 8}}$ $1/(16e^(-8))$

= $\frac{1}{\frac{16}{e^{8}}}$ $1/(16/e^8)$

= $\frac{e^{8}}{16}$ $e^8/16$

How do you simplify (2e^-2)^-4(2e−2)−4(2e^-2)^-4?