How do you simplify #(2e^-2)^-4#?

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Answer 1 · 2016-08-25T14:48:05

#(2e^(-2))^(-4)=e^8/16#

As #a^(-n)=1/a^n#

#(2e^(-2))^(-4)#

= #1/(2e^(-2))^4#

= #1/(2^4×e^(-8))#

= #1/(16e^(-8))#

= #1/(16/e^8)#

= #e^8/16#