How do you simplify $2 \sqrt{- \frac{16}{7}}$ $2sqrt(-16/7)$ ?

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Answer 1 · 2015-12-13T22:23:27

$\frac{8 \sqrt{7} i}{7}$ $(8sqrt7i)/7$

This can be rewritten as

$2 \sqrt{- 1 \times \frac{16}{7}}$ $2sqrt(-1xx16/7)$

$= 2 i \sqrt{\frac{16}{7}}$ $=2isqrt(16/7)$

$= \frac{2 i \sqrt{16}}{\sqrt{7}}$ $=(2isqrt(16))/sqrt7$

$= \frac{8 i}{\sqrt{7}}$ $=(8i)/sqrt7$

$= \frac{8 i}{\sqrt{7}} (\frac{\sqrt{7}}{\sqrt{7}})$ $=(8i)/sqrt7(sqrt7/sqrt7)$

$= \frac{8 \sqrt{7} i}{7}$ $=(8sqrt7i)/7$

Notice that the $i$ $i$ is not included in the square root in the final answer.

How do you simplify 2√−1672sqrt(-16/7)?