Question

How do you simplify `(2x^-3y^-2)/z^4` using only positive exponents?

Answer 1

`2/{x^{3}y^{2}z^4}`

Explanation:

Since `x^{-1}=1/x`, we have `x^{-3}=1/x^3` and `y^{-2}=1/y^2`, so you get

`{2x^{-3}y^{-2}}/z^4=2/{x^{3}y^{2}z^4}`