How do you simplify #(2x-y+3z)^2#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Alan P. Aug 12, 2015 #(2x-y+3z)^2# #color(white)("XXXX")##color(white)("XXXX")##= 4x^2-4xy+12xz+y^2-6yz+9z^2# Explanation: #{: (color(red)(xx), color(red)(" |"), color(red)(2x), color(red)(-y), color(red)(+3z)), (color(red)("---"),color(red)("-+-"),color(red)("------"),color(red)("------"),color(red)("------")), (color(red)(2x), color(red)(" |"), 4x^2, -2xy, +6xz), (color(red)(-y), color(red)(" |"), -2xy, +y^2, -3yz), (color(red)(+3z),color(red)(" |"),+6xz, -3yz, +9z^2) :}# Grouping terms with identical variable factors: #color(white)("XXXX")##= 4x^2-4xy+12xz+y^2-6yz+9z^2# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 5250 views around the world You can reuse this answer Creative Commons License