How do you simplify ${(- 2 x y^{4} z^{2})}^{5}$ $(-2xy^4z^2)^5$ ?

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How do you simplify ${(- 2 x y^{4} z^{2})}^{5}$ $(-2xy^4z^2)^5$ ?

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Answer 1 · 2014-12-15T17:43:01

In order to simplify the expression ${(- 2 x y^{4} z^{2})}^{5}$ $(-2xy^4z^2)^5$ we need to understand that the exponent 5 gets distributed to each term in the parenthesis.

$- 2^{5} x^{5} y^{4 (5)} z^{2 (5)}$ $-2^5x^5y^(4(5))z^(2(5))$

$- 2^{5}$ $-2^5$ (-2)(-2)(-2)(-2)(-2) = -32

$x^{5}$ $x^5$ = $x^{5}$ $x^5$

$y^{4 (5)}$ $y^(4(5))$ = $y^{20}$ $y^20$

$z^{2 (5)}$ $z^(2(5))$ = $z^{10}$ $z^10$

Final Answer

$- 32 x^{5} y^{20} z^{10}$ $-32x^5y^20z^10$

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How do you simplify ${(- 2 x y^{4} z^{2})}^{5}$ $(-2xy^4z^2)^5$ ?

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