How do you simplify #((-3)^0 x^4 y^-1) /( x^-1 yz ^-2)#?

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Answer 1 · 2017-01-26T22:41:11

#((-3)^0 x^4 y^-1) /( x^-1 yz ^-2)=(x^5z^2)/y^2#

Some rules which apply to indices:

#a^0-=1,# #"given"# # a!=0#

#a^m/a^n-=a^(m-n),# #"given"# # m-n>0# #"where"# #a=0#

#a^(-n)-=1/(a^n),# #"given"# #a!=0#

#-3^0=1#

#x^4/x^-1=x^(4--1)=x^5#

#y^-1/y=y^(-1-1)=y^-2#

#(1(z^0))/z^-2=z^(0--2)=z^2#

#((-3)^0 x^4 y^-1) /( x^-1 yz ^-2)=x^5y^-2z^2=x^5 1/y^2 z^2=(x^5z^2)/y^2#