How do you simplify $3^{2} (2^{2} - 1^{2}) + 4^{2}$ $3^2(2^2-1^2)+4^2$ ?

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How do you simplify $3^{2} (2^{2} - 1^{2}) + 4^{2}$ $3^2(2^2-1^2)+4^2$ ?

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Answer 1 · 2016-12-27T21:05:38

$43$ $43$

Explanation:

When evaluating expressions with $mixed operations$ $color(blue)"mixed operations"$ there is a particular order that must be followed.

Using the order as set out in the acronym PEMDAS [Parenthesis(brackets) , Exponents(powers), Multiplication, Division, Addition ,Subtraction]

$\Rightarrow 9 (4 - 1) + 16 = 9 \times 3 + 16 \leftarrow exponents/bracket$ $rArr9(4-1)+16=9xx3+16larr" exponents/bracket"$

$= 27 + 16 \leftarrow multiplication$ $=27+16larr" multiplication"$

$= 43 \leftarrow addition$ $=43larr" addition"$

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