How do you simplify $(30-i)-(18+6i)+30i$ and write the complex number in standard form?

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Answer 1 · 2017-04-01T16:40:03

$12+23i$

$(30-i)-(18+6i)+30i$

expand brackets:

$30-i-18-6i+30i$

collect like terms:

$30-i-18-6i+30i=12+23i$

standard form: $a+bi$
hence, $12+23i$ is in standard form.

How do you simplify (30-i)-(18+6i)+30i(30-i)-(18+6i)+30i and write the complex number in standard form?