How do you simplify #-3a^2b(9a^2-4b^2)#? Algebra Polynomials and Factoring Multiplication of Monomials by Polynomials 1 Answer BRIAN M. Oct 30, 2014 In order to simplify #-3a^2b(9a^2-4b^2)# you would use the distributive property and multiply #-3a^2b# by each of the terms in the parenthesis. #-3a^2b(9a^2)# - #-3a^2b(4b^2)# #(a^2)(a^2)# = (a)(a)(a)(a) = #a^4# #(b)(b^2)# = (b)(b)(b) = #b^3# #-27a^4b - (-12a^2b^3)# Simplify the signs. #-27a^4b + 12a^2b^3# Answer link Related questions What is Multiplication of Monomials by Polynomials? How do you multiply monomials by polynomials? How do you multiply monomials by monomials? How do you multiply #(3xy^5)(-6x^4y^2)#? How do you multiply and simplify #6ab(-10a^2 b^3+c^5)#? How do you multiply #y(xy^4)#? How do you multiply #(2x-1)(x^3-2x^2+3x-4)#? How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#? How do you simplify #2t^2+(3+5)(4t)#? How do you multiply #6a ^ -4 (a ^ 5 + 3x ^2 )#? See all questions in Multiplication of Monomials by Polynomials Impact of this question 3940 views around the world You can reuse this answer Creative Commons License