How do you simplify $(3b)/(-5c^-1)$ and write it using only positive exponents?

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Answer 1 · 2017-07-23T10:36:28

$(3bc)/(-5)$ or $-(3bc)/5$

$x^-a$ generally equates to $1/x^a$ , so:
$1/c^-1=(c^-1)^-1$

$=c^(-1\cdot(-1))$ applying exponential multiplication
$=c^1$ simplified; also equals $c$

replacing into original:

$(3b)/(-5c^-1)$
$(3bc)/(-5)$ or $-(3bc)/5$

How do you simplify (3b)/(-5c^-1)(3b)/(-5c^-1) and write it using only positive exponents?