How do you simplify ((3x^-2 y^3 )/(2xy))^-2(3x−2y32xy)−2?
1 Answer
Oct 11, 2015
Explanation:
Try to simply the expression
(3x^(-2)y^3)/(2xy)3x−2y32xy
first, then worry about the
Notice that you can write
(3x^(-2)y^3)/(2xy) = (3 * y^3)/(2xy) * 1/x^2 = (3y^2)/(2x^3)3x−2y32xy=3⋅y32xy⋅1x2=3y22x3
The original expression now becomes
((3y^2)/(2x^3))^(-2) = ((2x^3)/(3y^2))^2 = (2^2 * x^(3 * 2))/(3^2 * y^(2 * 2)) = color(green)((4x^6)/(9y^4))(3y22x3)−2=(2x33y2)2=22⋅x3⋅232⋅y2⋅2=4x69y4