How do you simplify ((3x^-2 y^3 )/(2xy))^-2(3x2y32xy)2?

1 Answer
Oct 11, 2015

(4x^6)/(9y^4)4x69y4

Explanation:

Try to simply the expression

(3x^(-2)y^3)/(2xy)3x2y32xy

first, then worry about the -22 exponent.

Notice that you can write

(3x^(-2)y^3)/(2xy) = (3 * y^3)/(2xy) * 1/x^2 = (3y^2)/(2x^3)3x2y32xy=3y32xy1x2=3y22x3

The original expression now becomes

((3y^2)/(2x^3))^(-2) = ((2x^3)/(3y^2))^2 = (2^2 * x^(3 * 2))/(3^2 * y^(2 * 2)) = color(green)((4x^6)/(9y^4))(3y22x3)2=(2x33y2)2=22x3232y22=4x69y4