Question

How do you simplify `(3x^4y^5)^ -3`?

Answer 1

`1/(27x^12y^15)`

Explanation:

Recall that `(x^ay^bz^c)^d=x^(ad)y^(bd)z^(cd)`. In other words, when something that already has an exponent is being raised to another exponent, you can just multiply the values of the exponents.

So, `(3x^4y^5)^-3=3^-3x^-12y^-15`

Also, recall that `a^-b=1/(a^b)`.

`3^-3x^-12y^-15=1/(3^3x^12y^15)=1/(27x^12y^15)`