How do you simplify $(3y^4)^5/y^-6$ ?

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Answer 1 · 2018-06-04T16:39:03

$243y^26$

We get
$(3y^4)^5=3^5y^20$
so
$(3^5y^20)/y^(-6)=243*y^26$

Answer 2 · 2018-06-04T16:43:31

$=243y^(26)$

First rule of exponents we use is:

$(a^n)^m = a^(n*m)$

$=(3y^4)^5/y^-6$

$=(3^(1*5)y^(4*5))/y^-6$

$=(3^(5)y^20)/y^-6$

$=(243y^20)/y^-6$

New we use the rule for quotients of exponents:

$a^n/a^m = a^(n-m)$

$=(243y^20)/y^-6$

$=243y^(20-(-6))$

$=243y^(26)$

How do you simplify (3y^4)^5/y^-6(3y^4)^5/y^-6?