How do you simplify #4 1/4 div 3 2/5#?

1 Answer
Alan P.
Jun 30, 2016

Convert the components into improper fractions; replace the division by multiplication by the inverse, to get: #color(blue)(20)#

Explanation:

#4 1/4div 3 2/5#

#color(white)("XXX")=17/4div 17/5#

#color(white)("XXX")=17/4xx5/17#

#color(white)("XXX")=4xx5#

#color(white)("XXX")=20#

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