How do you simplify $4^{3} - (2 + 2^{3}) \times 5$ $4^3 - (2+2^3) times 5$ using order of operations?

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Answer 1 · 2018-04-04T09:52:08

$\Rightarrow 14$ $color(blue)(=> 14$

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Given : $4^{3} - (2 + 2^{3}) \cdot 5$ $4^3 - (2 + 2^3) * 5$

Follow BODMAS or PEMDAS rule.

$\Rightarrow 4^{3} - 2 \cdot 5 - 2^{3} \cdot 5, removing Braces$ $=> 4^3 - 2*5 - 2^3 * 5, " removing Braces "$

$\Rightarrow 64 - 2 \cdot 5 - 8 \cdot 5, Orders or exponents$ $=> 64 - 2 * 5 - 8 * 5, " Orders or exponents"$

$\Rightarrow 64 - 10 - 40, Multiplication$ $=> 64 - 10 - 40, " Multiplication "$

$\Rightarrow 14, Subtraction$ $=> 14, " Subtraction "$

How do you simplify 43−(2+23)×54^3 - (2+2^3) times 5 using order of operations?