How do you simplify $4(3^2+3)$ using PEMDAS?

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Answer 1 · 2016-03-29T20:54:27

$4(3^2+3)=48$

first evaluate the part in the brackets to get

$(3^2+3)=9+3=12$

Now multiply this result by $4$ to get

$4xx12=48$ .

How do you simplify 4(3^2+3) 4(3^2+3) using PEMDAS?