How do you simplify #4^-(5/2)#?
1 Answer
Jan 17, 2017
Explanation:
Using the
#color(blue)"laws of exponents"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^-mhArr1/a^m)color(white)(2/2)|)))#
#rArr4^(-5/2)=1/4^(5/2)#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^(m/n)hArr(root(n)a)^m)color(white)(2/2)|))#
#rArr4^(5/2)=(root(2)4)^5=(2)^5=32#
#rArr4^(-5/2)=1/4^(5/2)=1/32#
