How do you simplify $(- 4 - 6 i) + (- 2 - 3 i)$ $(-4 - 6i) + (-2 - 3i)$ and write in a+bi form?

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How do you simplify $(- 4 - 6 i) + (- 2 - 3 i)$ $(-4 - 6i) + (-2 - 3i)$ and write in a+bi form?

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Answer 1 · 2015-11-21T14:53:26

$- 6 - 9 i$ $-6-9i$

Explanation:

Treat the imaginary $i$ $i$ just like you would an $x$ $x$ .

$(- 4 - 6 i) + (- 2 - 3 i)$ $(-4-6i)+(-2-3i)$

$- 4 - 6 i - 2 - 3 i$ $-4-6i-2-3i$

$- 4 - 2 - 6 i - 3 i$ $-4-2-6i-3i$

$(- 4 - 2) + (- 6 i - 3 i)$ $(-4-2)+(-6i-3i)$

$- 6 - 9 i$ $-6-9i$

Notice that this is in $a + b i$ $a+bi$ form: the term without the $i$ $i$ comes first.

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How do you simplify $(- 4 - 6 i) + (- 2 - 3 i)$ $(-4 - 6i) + (-2 - 3i)$ and write in a+bi form?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you simplify (−4−6i)+(−2−3i) (-4 - 6i) + (-2 - 3i) and write in a+bi form?

1 Answer

Explanation:

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Impact of this question

How do you simplify $(- 4 - 6 i) + (- 2 - 3 i)$ $(-4 - 6i) + (-2 - 3i)$ and write in a+bi form?