How do you simplify $4/(x+3) –6/(x-3)$ ?

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Answer 1 · 2015-02-04T15:07:40

The answer is: $-2(x+15)/((x+3)(x-3))$ .

The least common denominator of the two denominators $x+3$ and $x-3$ is:

$(x+3)(x-3)$ ,

so:

$4/(x+3)-6/(x-3)=(4(x-3)-6(x+3))/((x+3)(x-3))=$

$=(4x-12-6x-18)/((x+3)(x-3))=(-2x-30)/((x+3)(x-3))=$

$=-2(x+15)/((x+3)(x-3))$ .

How do you simplify 4/(x+3) –6/(x-3)4/(x+3) –6/(x-3)?