How do you simplify #4r^-3 * 2r^2#?

1 Answer
Don't Memorise
Mar 11, 2016

# = 8 / r#

Explanation:

#4r^-3 * 2r^2#

# = color(blue)(4) * r^-3 * color(blue)(2) * r^2#

# =color(blue)( 4* 2) * r^-3 * r^2#

# = color(blue)(8 ) * r^-3 * r^2#

  • As per property:
    #color(green)(a^m * a^n = a^(m+n)#

# = color(blue)(8 ) * color(green)( r^ (-3 +2)#

# = color(blue)(8 ) * color(green)( r^ (-1)#

  • As per property:
    #a^-1 = 1/a#

# color(blue)(8 ) * color(green)( r^ (-1))= 8 * 1/ r#

# = 8 / r#

Related questions
See all questions in Negative Exponents
Impact of this question
17620 views around the world
You can reuse this answer
Creative Commons License