How do you simplify #(4x ^ { - 2} ) ^ { 3} ( 3x ^ { 6} ) ^ { 4}#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer anor277 Oct 19, 2016 #(4x^(-2))^3(3x^6)^4=5184x^18# Explanation: #(4x^(-2))^3(3x^6)^4=4^3(x^(-2))^3(3x^6)^4=# #4^3xxx^-6xx3^4xxx^24=# #4^3xx3^4xxx^(24-6)=64xx81xxx^18# #5184x^18# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1664 views around the world You can reuse this answer Creative Commons License