How do you simplify # (5^0)^-2 + 2^-3#?
1 Answer
Feb 29, 2016
Explanation:
A reminder of how to deal with negative exponents:
#a^-b=1/a^b#
Thus, the expression equals
#=1/(5^0)^2+1/2^3#
To deal with
#=1/1^2+1/8#
#=1+1/8#
#=9/8#