How do you simplify $(5^{2} \cdot 2 - 8) \div [3 (3^{2} - 2)]$ $(5^2 * 2 - 8) ÷ [3(3^2 - 2)]$ ?

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Answer 1 · 2018-05-02T04:58:42

$\Rightarrow 2$ $color(blue)(=>2)$

$\frac{5^{2} \cdot 2 - 8}{3 \cdot (3^{2} - 2)}$ $(5^2 * 2 - 8) / [3 * (3^2 -2)]$

![https://www.onlinemath4all.com/http://pemdas-rule.html](https://useruploads.socratic.org/bYCSEUJOQmKa4cZKWnME_pemdas.png)

Following the order of operations $PEMDAS$ $color(indigo)("PEMDAS"$

$\Rightarrow \frac{5^{2} \cdot 2 - 8}{3 \cdot 3^{2} - 3 \cdot 2}, Removing bracket$ $=> (5^2 * 2 - 8) / [3*3^2 - 3*2], color(red)("Removing bracket"$

$\Rightarrow \frac{25 \cdot 2 - 8}{3 \cdot 9 - 3 \cdot 2}, expanding exponent$ $=> (25 * 2 - 8) / [3*9 - 3*2], color(red)("expanding exponent"$

$\Rightarrow \frac{50 - 8}{27 - 6}, multiplying$ $=>(50 - 8) / (27 - 6), color(red)("multiplying"$

$\Rightarrow \frac{42}{21}, removing braces$ $=> 42 / 21, color(red)("removing braces"$

$=> cancel(42)^color(blue)(2) / cancel 21 = 2$

How do you simplify (5^2 * 2 - 8) ÷ [3(3^2 - 2)](52⋅2−8)÷[3(32−2)](5^2 * 2 - 8) ÷ [3(3^2 - 2)]?