How do you simplify $5(2^3+4)/sqrt36 times 7$ ?

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Answer 1 · 2016-04-15T14:59:41

$(5 (2^3+4)/sqrt36)xx7=(5 12/6)xx7=(5+2)xx7=49$

OR if there exists a dot
$(5. (2^3+4)/sqrt36)xx7=(5 xx12/6)xx7=(5xx2)xx7=70$

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How do you simplify 5(2^3+4)/sqrt36 times 75(2^3+4)/sqrt36 times 7?