How do you simplify $5 + [30 - {(6 - 1)}^{2}]$ $5+[30-(6-1)^2]$ ?

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Answer 1 · 2015-07-26T19:32:35

$5 + [30 - {(6 - 1)}^{2}] = 10$ $5+[30-(6-1)^2]=10$

$5 + [30 - {(6 - 1)}^{2}]$ $5+[30-(6-1)^2]$

Perform the subtraction inside the parentheses.

$6 - 1 = 5$ $6-1=5$

$5 + [30 - {(5)}^{2}]$ $5+[30-(5)^2]$

Square the $5$ $5$ inside the brackets.

$5^{2} = 25$ $5^2=25$

$5 + [30 - 25]$ $5+[30-25]$

Perform the subtraction inside the brackets.

$5 + 5$ $5+5$ =

$10$ $10$

How do you simplify 5+[30−(6−1)2]5+[30-(6-1)^2]?