How do you simplify #5/abs(-2)#? Algebra Properties of Real Numbers Additive Inverses and Absolute Values 1 Answer Alan P. May 31, 2015 Since #abs(-2) = 2# #5/abs(-2) = 5/2 = 2½# Answer link Related questions What are absolute values? What is the absolute value of -10 and 10? How do you know that the additive inverse of -20 is 20? How do you evaluate #|2-8|#? How do you simplify #-|-1|#? What is the additive inverse property? What is the absolute value of -9? How do you simplify #x = - abs6^2 - abs(-4 + 7) *7#? How do you simplify #abs( -11 +1)#? How do you simplify #abs6-abs(-3)#? See all questions in Additive Inverses and Absolute Values Impact of this question 1930 views around the world You can reuse this answer Creative Commons License