How do you simplify $6+12/3*2-(4+3)+2^3$ using PEMDAS?

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Answer 1 · 2016-03-01T13:37:28

Well, let's start with Paretheses:

P: $=6+12/3*2-7+2^3$
E: $=6+12/3*2-7+8$
MD: $=6+4*2-7+8=6+8-7+8$

AS: $=15$

Remember:
Multiplication and Division, and (in the following step) Adding and Subtracting go from left to right, in order.

How do you simplify 6+12/3*2-(4+3)+2^36+12/3*2-(4+3)+2^3 using PEMDAS?