How do you simplify $6 {13 - 2 (4 + 1)}$ $6{13-2(4+1)}$ ?

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Answer 1 · 2018-03-22T16:44:04

See below.

When solving problems like this it is good practice to work from the inside out.

$6 {13 - 2 (4 + 1)}$ $6{13-2(4+1)}$

Start with the terms in parenthesis:

$6 {13 - 2 (5)}$ $6{13-2(5)}$

Multiply by the number outside the parenthesis:

$6 {13 - 10}$ $6{13-10}$

Subtract the terms inside the braces:

$6 {3}$ $6{3}$

Mutiply by the number outside of the braces:

$18$ $18$

How do you simplify 6{13−2(4+1)}6{13-2(4+1)}?