Question

How do you simplify `6 ÷ (17 - 11) times 14` using order of operations?

Answer 1

See a solution process below:

Explanation:

First, execute the operation within the Parenthesis;

`6 -: (color(red)(17) - color(red)(11)) xx 14 =>`

`6 -: 6 xx 14`

Next, execute the Multiplication and Division operations from left to right:

`color(red)(6) -: color(red)(6) xx 14 =>`

`1 xx 14 =>`

`14`

Answer 2

14 !!

Explanation:

It could be written as `6/(6)*14`= 1*14=14
Just use the BODMAS principle giving more preference to division than to multiplication.

Answer 3

14

Explanation:

Order of operations follows this order:
- P (Parentheses)
- E (Exponents)
- MD (Multiplication and Division - left to right)
- AS (Addition and Subtraction - left to right)
Or PEMDAS for short.

So when we see:
`6÷(17−11)×14`
We know do the Parentheses first. So lets solve the part inside the parentheses:
`6÷(6) ×14`
There aren't any Exponents in this equation, so we can skip that part. But there is multiplication and division! So we will solve the those parts (don't forget: Go left to right! )
`6÷6 ×14`
`1 ×14`
`14`